A sealed container holding 0.0255 L of an ideal gas at 0.991 atm and 73 degrees

Question

A sealed container holding 0.0255 L of an ideal gas at 0.991 atm and 73 degrees C is placed into a refrigerator and cooled to 37 degrees C with no change in volume. Calculate the final pressure of the gas. saplinglearning.com Lecture slides... Untitled Untitled Untitled Terms of Us ollege-CHEM 1315-Fall17-DECKERActivities and Due Dates HW9 10/27/2017 06:00 PM 2.1/40 Grade Print Calculator Periodic Table estion 2 of 19 Map Sapling Learning A sealed container holding 0.0255 L of an ideal gas at 0.991 atm and 73 is placed into a refrigerator and cooled to 37 with no change in volume. Calculate the final pressure of the gas Number atm Tools x 10 O Previcus Give up & View Solon 9Chook Answer ONet tlex Hint

Explanation / Answer

At 73°C,

V= 0.0255 L; T= 273+73=346 K; R= 0.08206; P=0.991 atm

Formula-

PV=nRT

n= PV/RT= (0.991 x 0.0255)/(0.08206 x 346)

n= 0.02527/28.3927=0.00089 mol

At 37°C,

V= 0.0255 L; T= 273+37=310 K; R= 0.08206; n= 0.00089 mol

P=?

Formula-

PV=nRT

P x 0.0255= 0.00089 x 0.08206 x 310

P= (0.00089 x 0.08206 x 310)/ 0.0255 atm

= 0.02264/0.0255 atm

= 0.887 atm

The pressure at 37°C is 0.887 atm

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