Answer all questions clearly and correctly potent actions landins are a class of

Question

Answer all questions clearly and correctly potent actions landins are a class of eicosanoids, fatty acid derivatives with a variety of extremely Prostagl on vertebrate tissues. They are Prostaglandins are derved from the 20-carbon fatty acld arachidonic acld in a reaction catalyzed by the enzyme prostaglandin endoperoxide smthase. This enzyme, a cyclooxygenase, uses oxygen to convert arachidonic acid to PGG2, the immediate precursor of many difterent prostaglandins responsible for producing fever and inflammátion and its ássociated pain Rate of formation The kinetic data given in the table are for the Arachidonic acid Rate of formationof PGG2 reaction catalyzed by a mutant of prostaglandin endoperoxide synthase. Focusing here on the first two columns, determine the Vmx and Km of the enzyme. (mM) with 10 mg/mL 0.165 0.198 0.297 0.495 1.16 of PGG2 (mWmin) 14.3 16.1 20.4 25.8 33.5 8.96 10 3 13.8 19.0 27.9 Number mM/ mirn Number mM Please scroll down

Explanation / Answer

Lineweaver-burk plot need to be created for determination of KM and Vmax. The equation is given by

1/V =KM/Vmax)*1/S + 1/Vmax

so a plot of 1/V vs 1/S need to be created which gives a straight line. The slope is given by KM/Vmax and intercept is 1/Vmax.

In case of presence of an inhibitor ibuprofen, the equation still remains straight line but with slope of KMapp/Vmaxapp and intercept of 1/Vmaxapp.

V= rate of formation of PGG2. S= concentration of Arachidonic acid

So a plot of 1/V vs 1/S nee to be generated for both in the absence and presence of iuprofen.

The plot along with the data points are shown below.

from the plot in the absence of ibuprofen inhibitor, the equation of best fit is 1/V= (0.014)*1/S + 0.023

1/Vmax= 0.023, intercept, Vmax= 1/0.023= 43.5 mM.min, Slope = KM/Vmax= 0.014, Km=0.014*43.5 mM=0.609 MM

In the presece of ibuprofen inhibitor, The equation of best fit is 1/V= (0.007)*1/S +0.023

1/Vmax app =0.023, Vmaxapp =1/0.023=43.5 mM/min and Slope = KM/Vmax= 0.007, KM=0.007*43.5 =0.3045 mM

since Vmax and Vmax app are same, the type of inhibition is competitive inhibition where binding of the inhibitor to the active site on the enzyme prevents binding of the substrate and vice- versa.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.