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Jump to... lege -CHEM 100-Fall17-MADANI Activities and DueDates HW 11-12 11/8/20

ID: 557191 • Letter: J

Question

Jump to... lege -CHEM 100-Fall17-MADANI Activities and DueDates HW 11-12 11/8/2017 11:55 PM 36.7/100 Print Calculator Gradeba Periodic Table uestion 6 of 30 Mapm Sapling Learning A gas-filled weather balloon has a volume of 53.0 L at ground level, where the pressure is 759 mmHg and the temperature is 204 After being released the balloon nses to an altitude where the temperature is -6.30 °C and the pressure is 0.0595 atm. What is the weather balloon's volume at the higher altitude? Number 8 80 FS F 7 8

Explanation / Answer

step1:

use ideal gas equation

PV=nRT

where P= PRESSSURE,

V= VOLUME

R= GAS CONSTANT ,

T= TEMPERATURE

for our problem we have

pressure in mmHg, temperature in celcius, volume in litre so corresponding gas constant is:

R=62.363 L mmHg K1 mol1

so just convert now temperature into kelvin using scale:

T(K)=273+ T(C)

Solution using all:  

initial values:

P1=759 mmHg

T1=20.4 C= 293.4 k

V1= 53 L,

so using ideal gas equation number of moles of gas in ballon =n:

P1*V1= n*R*T1

n*R=P1*V1/T1.......................(1)

finally we have

P2=0.0595 atm= 45.22 mmHg

T2=-6.30 C= 266.7 k

V2= ? L,

so using ideal gas equation number of moles of gas in ballon remains same =n:

P2*V2= n*R*T2

n*R=P2*V2/T2.......................(2)

so now solve both equation (1)= (2) we get V2:

V2=808.63 L