Calculate the boiling point of a water solution at each concentration. Part A 0.

Question

Calculate the boiling point of a water solution at each concentration.

Part A

0.225 m

Express your answer using three decimal places.

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Part B

3.78 m

Express your answer using two decimal places.

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Part C

4.33 m

Express your answer using two decimal places.

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Part D

7.77 m

Express your answer using two decimal places.

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Calculate the boiling point of a water solution at each concentration.

Part A

0.225 m

Express your answer using three decimal places.

Boiling Point =   C  

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Part B

3.78 m

Express your answer using two decimal places.

Boiling Point =   C  

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Part C

4.33 m

Express your answer using two decimal places.

Boiling Point =   C  

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Part D

7.77 m

Express your answer using two decimal places.

Boiling Point =   C  

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Explanation / Answer

A)

lets now calculate deltaTb

deltaTb = Kb*m

= 0.512*0.225

= 0.1152 oC

This is increase in boiling point

boiling point of pure liquid = 100.0 oC

So, new boiling point = 100 + 0.1152

= 100.1152 oC

Answer: 100.115 oC

B)

lets now calculate deltaTb

deltaTb = Kb*m

= 0.512*3.78

= 1.9354 oC

This is increase in boiling point

boiling point of pure liquid = 100.0 oC

So, new boiling point = 100 + 1.9354

= 101.9354 oC

Answer: 101.935 oC

C)

lets now calculate deltaTb

deltaTb = Kb*m

= 0.512*4.33

= 2.217 oC

This is increase in boiling point

boiling point of pure liquid = 100.0 oC

So, new boiling point = 100 + 2.217

= 102.217 oC

Answer: 102.217 oC

D)

lets now calculate deltaTb

deltaTb = Kb*m

= 0.512*7.77

= 3.9782 oC

This is increase in boiling point

boiling point of pure liquid = 100.0 oC

So, new boiling point = 100 + 3.9782

= 103.978 oC

Answer: 103.978 oC

Feel free to comment below if you have any doubts or if this answer do not work. I will correct it and submit again if you let me know

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