saplinglearning.com (6) YouTube The Following Possible Reactions I Chegg.com Jum

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saplinglearning.com (6) YouTube The Following Possible Reactions I Chegg.com Jump to Natanael Toribi t Set 2/ Calculator -el Periodic Table Print Ma Sapling Learning Classify each of the following possible reactions according to whether a precipitate will form or will not form. Precipitate forms No reaction CrCl; + Li2CO3 ? KI + Pb(NO3)2 ? KI + NaCl --> KOH + FeCl 3 · LiNO3+ Na2SO4 ? There is additional feedback available! View this feedback by clicking on the bottom divider bar on the divider Incorrect. bar again to hide the additional feedback. Close O Previous Give Up & View Solutm #Try Again Explanation O Next tlExi 13

Explanation / Answer

1)

Precipitate form

2KI(aq) + Pb(NO3)2(aq) --------> PbI2(s) + 2KNO3(aq)

3KOH(aq) + FeCl3(aq) ------> Fe(OH)3(s) + 3KCl(aq)

CrCl2(aq) + Li2CO3(aq) ------> CrCO3(s) + 2LiCl(aq)

No precipitate

KI + NaCl -------->

LiNO3 + Na2SO4 -------->

2)

2S2O32- (aq) + I3-(aq) -------> S4O62-(aq) + 3I-(aq)

Stoichiometrically, 2mole of S2O32- react with 1 mole of I3-

Mole of S2O32- consumed =( 0.480mol/1000ml)×32.3ml = 0.015504mol

So, Mole of I3-reacted = 0.015504/2 = 0.007752mol

Volume of I3- solution = 25ml

Molarity of I3-(aq)=(0.007752mol/25ml)×1000ml =0.3101M

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