Given that the HCl Volume from Equivalence Point is 10.5mL 30mL of 0.050 M HCl s

Question

Given that the HCl Volume from Equivalence Point is 10.5mL

30mL of 0.050 M HCl solution

Summary Data Table Determining the Ksp of Calcium Hydroxide CHEZ 102 lab Section Name Lab Partner, Date DATA TABLE Ca(OH)2 Volume (mL) HCI Volume (mL) from Equivalence Point Ca(OH)2 Titration 15.0 DATA ANALYSIS 1. Calculate the [OH] from your titration result. Do your calculations in your lab notebook. [OH-] = 2. Calculate the [Ca2]. Explain or show your calculation in your lab notebook. [Ca21 3. Calculate the Ksp for calcium hydroxide. Show and explain your calculation in your lab notebook. Experimental Ksp 4. Find the accepted value of the Kip for calcium hydroxide. It is in your textbook. Actual K,-

Explanation / Answer

Given that the HCl Volume from Equivalence Point is 10.5mL

30mL of 0.050 M HCl solution is taken for the experiment.

1. [OH-]= 10.5 ml * 0.050(M) / 30 ml = 0.0175 (M)

2. We know that, 2*[Ca2+]= [OH-]

Now, [Ca2+]= [OH-]/2= 0.0175/2 (M) = 0.00875(M)

3. Ksp= 1/2 *  [OH-]3 = 1/2 *  [0.0175]3 = 2.68 * 10-6 (Experimental)

4. Actual Ksp= 6.5 * 10-6

Related Questions

Navigate

• Browse (All)
• Browse G
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.