Given that the HCl Volume from Equivalence Point is 10.5mL; 30mL of 0.050 M HCl

Question

Given that the HCl Volume from Equivalence Point is 10.5mL; 30mL of 0.050 M HCl solution

Summary Data Table Determining the Ksp of Calcium Hydroxide CHEZ 102 lab Section Name Lab Partner, Date DATA TABLE Ca(OH)2 Volume (mL) HCI Volume (mL) from Equivalence Point Ca(OH)2 Titration 15.0 DATA ANALYSIS 1. Calculate the [OH] from your titration result. Do your calculations in your lab notebook. [OH-] = 2. Calculate the [Ca2]. Explain or show your calculation in your lab notebook. [Ca21 3. Calculate the Ksp for calcium hydroxide. Show and explain your calculation in your lab notebook. Experimental Ksp 4. Find the accepted value of the Kip for calcium hydroxide. It is in your textbook. Actual K,-

Explanation / Answer

Ksp for Ca(OH)2

a) with volume of HCl to equivalence point = 30 ml

moles HCl used = 0.05 M x 30 ml = 1.5 mmol

Ca(OH)2 reacted = 1.5/2 = 0.75 mmol

Molarity of Ca(OH)2 = 0.75 mmol/15 ml = 0.05 M

[OH-] = 2 x 0.05 M = 0.10 M

b) [Ca2+] = 0.05 M

c) Ksp = [Ca2+][OH-]^2

           = (0.05)(0.10)^2

           = 5 x 10^-4 M

d) literature Ksp Ca(OH)2 = 5.5 x 10^-6

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