Calculate the number of calories required to raise 10.0 g of water from 25.0 C t

Question

Calculate the number of calories required to raise 10.0 g of water from 25.0 C to 75.0 °C. The ecific heat of water is 1.00 cal/(gxC). A) 10.0 cal B) 50.0 cal C) 2.50 x 102 cal D) 5.00 x 102 cal 7.50 x 102 cal 11.)Calculate the heat absorbed when 10.0 g of ice at 0 °C melts to water at the same temperature. The specific heat of water is 1.00 cal/(g x °C); the heat of fusion is 80.0cal/g; and the heat of vaporization is 540.0 cal/g. A) 8.0 cal B) 10.0 cal C) 54.0 cal D) 8.00 x 102 cal E) 5.40 x 103 cal 12, Calculate the heat required to convert 10.0 g of water at 25.0 °C to steam at 100.0 °C. The specific éat of water is 1.00 cal/(g x °C); the heat of fusion is 80.0 cal/g; and the heat of vaporization is 540.0 cal/g A) 7.50 x 102 cal B) 8.00 x 102 cal C) 1.05 x 103 cal D) 1.55 x 103 cal E) 6.15 x 103 cal

Explanation / Answer

10) q = mCp(T2 - T1)
q = 10gm * 1cal/g oC * (75-25)oC = 500 cal , option D) is the answer

11) q = m Hf = 10gm * 80 cal/gm = 800cal
Option D) is the answer

12) q1 = 10gm * 1cal/gmoC * (100-25)oC = 750 cal
q2 = m*Hv = 10gm*540cal/gm = 5400 cal
Total heat required to convert = 750cal + 5400 = 6150 cal
option E) is the answer

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