Finding the temperature in which G: 0. Anything after that temperature will resu

Question

Finding the temperature in which G: 0. Anything after that temperature will result in a nonspontaneous proc after that tempera set G = 0, Then solve for T. Practice Time: unburied iy drocerowing reaction ivolving the oxidation. Use the standard free energies of formation to determine Grn for this reaction at 25 °C. CH4(g) + 802 (g) CO2 (g) + 2 H2O (g) + 40, (g) (CHa(B)-50.5 kJ/mol; O2 - 0.0 kJ/mol; CO2(8) -394.4 k/mol; H20 (g)--228.6 kJ/mol; Os (8)- 163.2 k/mol) 3. When magnesium sulfite decomposes, the solid transforms into magnesium oxide and sulfur dioxide. MgS03(s) MgO(s) + SO2(g) At what temperature will this reaction be spontaneous according to Gibb's Energy? G in kJ/mol for: MgSO3 (s)-.-1172. Mg0(s)--569.6. SO2(g)--300.2 H in kJ/mol for: MgSO3(s)--I 068, MgOG) =-601.8, so2(g)--296.8 AS in J/mol K for: MgSO3(s) - 121, Mgo(s) a. temps below-63.1 K b. temps below 179.5 K c. temps below 415.8 K d. temps above 1100 K 27, SO28) 248.1

Explanation / Answer

Q1.

dG = Gproduct s- Greactants

dG = CO2 + 2H2O + 4O3 - -(CH$ + 8O2)

dG= -393.4 + 2*-228.6 + 4*163.2 - (-50.5 +8*0)

dG = -147.3 kJ/mol

Q3

dG = dH - T*dS

dH = (MgO + SO2)- (MgSO3)

dH= -601.8+-296.8 - -1068 = 169.4

dS = (MgO + SO2)- (MgSO3)

dS = (27+248.1-121) = 154.1 = 0.1541

dG = 169.4 - T * 0.1541

dG < 0

169.4 - T * 0.1541 < 0

169.4 < T * 0.1541

T > 169.4/0.1541 = 1099

T = 1099-273 = 826°C

choose D

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