Data The numbers below in black are the values you entered, the values in red ar

Question

Data The numbers below in black are the values you entered, the values in red are the randomized starting values provided to you, the numbers in blue are the correct calculated values based on your randomized starting values molecular mass (g) weight 211 (211.13) 32 (32.05) 174 (174.16) density vol reagent 3-nitrophthalic acid hydrazine (8% aq. wt/vol) mmoles equivalents (g/mL) (mL) 2.36 (2.3540 1) 3.156 0.497 0.101 1.2660 (3.1601) 1.3424) 1.015 1.0164) 1.3 1.266 2.47 (2.4792) sodium dithionite 5.836 theoretical product luminol Provide the name of the catalyst used for this reaction, if there was no catalyst used, write 0.417 0.4170 (2.3540) 2.36 (177.16) none none Your score for the prelab is: 9.5 The equivalents of hydrazine is incorrect

Explanation / Answer

mmol of hydrazine=3.156

So mol of hydrazine=3.156*10^-3 mol

mass of hydrazine=0.101g

molar mass of hydrazine=mass/mol=0.101g/3.156*10^-3 mol=32.0g/mol

equivalent weight of hydrazine=molecular weight/2 (as 2 lone pairs gives it an acidity of 2 ,it can accept two H+]

eqv weight=32.0/2=16.0 g/mol

So equivalents=mol weight/eqv weight=32.0/16.0=2.0

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.