Question 1 111 marks Butane gas (CAHo) at 25 °C and 0.IMPa is mixed with air at

Question

Question 1 111 marks Butane gas (CAHo) at 25 °C and 0.IMPa is mixed with air at the same temperature and pressure, and then burned in a steady-flow combustor. Note that the pressure inside of the combustor remains at 0.1MPa. In the case where 100% theoretical air is used, write down the chemical reaction equation. Determine the % theoretical air in the case where the chemical reaction equation reads 1.2C,He, + 15.6(, +3.76M)- 48CO, + 6H20+58.656N, +7.802 (2) b. c. The butane-air mixture ratio is now changed and the products of combustion analysed. The resulting reaction equation based on the measurements now reads C,Hio +13(0, t 3.76N, ) 2CO, +511,0-48.88N. +2C0+ 6.50, Would you say that the measurements were accurate? Substantiate your answer. (2) d. The percentage theoretical air is now again changed and such that the chemical reaction equation reads C,l,. T 13(02 + 3.76N, )-4CO. +511.0+48.88N, +6.50, Write down the steady-flow energy equation for the chemical reaction Question 2 112 markl

Explanation / Answer

a) C4H10 + 6.5 O2 ---> 4 CO2+5H2O This the chemical equation for 100% theoritical air used.

b)15.6-7.8 /15.6(initial number of mole of oxygen-final number of mole left behind/initial number of moles oxygen*100)

c) It is not accurate because of the moles balance of N2 is not matching.

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