Consider the 69 kg ice skater being pushed by two others shown in the figure. Th

Question

Consider the 69 kg ice skater being pushed by two others shown in the figure. The coefficient of static friction is m=0.4 and kinetic is Hk=0.02. Find the magnitude of F_to t: the total force exerted on her by the others, given that the magnitudes F and F2 are 235 N and 199 N, respectively in Newtons. Find the direction of Ft** (in degrees relative to the horizontal), the total force exerted on her by the others, given that the magnitudes F and F2 are 235 N and 199 N: respectively. What is her initial acceleration if she is initially stationary' and wearing steel-bladed skates that point in the direction of F_to t in m/s^2? What is her acceleration assuming she is already moving in the direction of F_tot in m/s^2?

Explanation / Answer

(a)

the magnitude of the total net force is,

F = sqrt[F1^2 + F2^2] =  sqrt[235^2 + 199^2] = 307.9 N

(B)

the direction of the net force is,

@ = tan^-1[199/235] = 40.26o

(c)

since the person is at rest positin initially, so the acceleration is zero.

(d)

the force is,

F =Ftot - umg = 307.9 - 0.02*69*9.8 = 294.376 N = 294.4 N

Acceleration is,

a = F/m = 294.376 / 69 = 4.26 m/s^2

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