6. Calculate the standard reaction enthalpy for the following reaction. CH4(g) +

Question

6. Calculate the standard reaction enthalpy for the following reaction. CH4(g) + H2O(g) CO(g) + 3H2(g) Given: 2H2(g) + CO(g) CH3OH(1) 2CH4(g) + 02(g) 2CH3OH(1) 2H2(g) + O2(g) 2H2O(g) 1° =-128.3 kJ-mol-1 -328.1 kJ-mol-1 AHo--483.6 kJ-mol1 Is the reaction exothermic or endothermic? 7. Given the equation for the reaction, CO2(g) + 4H2(g) CH(g) + 2H20(g), and the following standard enthalpies of formation, AHp: CO2(g): -393.5 kJ mol-1 CH4(g:-74.8 k] mol1 H20(g): -241.8 kJ mol-1 What is the standard enthalpy of reaction, in kJ for the reaction shown?

Explanation / Answer

6)

Lets number the reaction as 0, 1, 2, 3 from top to bottom

required reaction should be written in terms of other reaction

This is Hess Law

required reaction can be written as:

reaction 0 = -1 * (reaction 1) +0.5 * (reaction 2) -0.5 * (reaction 3)

So, deltaHo rxn for required reaction will be:

deltaHo rxn = -1 * deltaHo rxn(reaction 1) +0.5 * deltaHo rxn(reaction 2) -0.5 * deltaHo rxn(reaction 3)

= -1 * (-128.3) +0.5 * (-328.1) -0.5 * (-483.6)

= 206.05 KJ

Answer: 206.05 KJ

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