Can anyone help me out?You plan to perform artificial DNA synthesis using oligon

Question

Can anyone help me out?You plan to perform artificial DNA synthesis using oligonucleotides for construction of a synthetic gene. The sequence of the desired gene is shown below. The synthesis reaction can be performed at three different scales providing a total of 40 nmole, 1 µmole, or 10 µmole of starting material (i.e., synthesis at 100% yield would generate 0.04, 1, or 10 µmol of product, respectively). The cost of synthesis differs for each scale: $0.50/base, $1.00/base, and $2.00/base, respectively. The coupling efficiency of each nucleotide addition step is 98.3%. To assemble your oligonucleotides into the full-length gene, you require at least 28 nmol of the correct oligonucleotide product and you will need at least 15 bases of overlap between oligonucleotides for hybridization. What is the most economical synthesis scale (of the three possibilities) at which the oligonucleotide synthesis reactions can be conducted? Draw boxes on the sequence below to indicate the sequences of the oligonucleotides you would use es of overlap between oligonucleotides for hybridization. What is the most economical synthesis scale (of the three possibilities) at which the oligonucleotide synthesis reactions can be conducted? Draw boxes on the sequence below to indicate the sequences of the oligonucleotides you would use

Explanation / Answer

Well, the most economical scale should be 40nmol; because you have to synthesise only 28nmol. And this will contain as many repeats as the other two as well. The cost of this scale will be the least.

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