questions 5-7. Applying Hardy-Weinberg to pocket mouse field data. Dr. Nachman a
ID: 59784 • Letter: Q
Question
questions 5-7. Applying Hardy-Weinberg to pocket mouse field data. Dr. Nachman and his colleagues collected pocket mice across 35 km. of the Arizona Sonoran Desert that included both dark, rocky lava outcrops and light rocky granite areas. Substrate color and coat color frequencies were recorded for each location. Each site was separated from any of the others by at least 8 km. A total of 225 mice were trapped. His data are shown below:
5. Calculate the overall frequencies of light mice and dark mice caught on dark substrates.
Frequency of light mice ________ Frequency of dark mice ________
6. Calculate the overall frequencies of light mice and dark mice caught on light substrates.
Frequency of light mice ________ Frequency of dark mice ________
7. Using the Hardy-Weinberg equation and data from the table above, determine the number of mice with the DD and Dd genotypes on found on both the light granite substrate and the dark lava substrate.
Use the values you just determined to answer the following questions.
a). Which fur color seems to have the greatest overall selective advantage?
b). What might be some reasons for this advantage?
8. Niemann-Pick is an autosomal recessive disease in humans. Mutation of a gene involved in lipid storage called Sphingomyelin phosphodiesterase1 (SMPD1) is responsible for pleiotrophic phenotypic defects of an enlarged liver and spleen, and neurological disorders including unsteady gait, slurring of speech and the gradual loss of intellectual abilities. The incidence of Type A Niemann-Pick disease worldwide is 1 in 250,000.
Assuming random mating (i.e., Hardy- Weinberg equilibrium), what is the frequency of heterozygous carriers of Niemann-Pick in the worldwide population?
Explanation / Answer
8. Genotypic frequency of recessive allele = q2 = 1/250 000 = 0.00 0004
Allelic frequency = q = 0.002
p+q = 1
p = 1-0.002 = 0.998.
Frequency of carriers = 2pq = 2 * 0.002 * 0.998 = 0.003992 or 0.3992% people were affected with Niemann Pick disease.
Out of 250,000 it would be = 0.3992 * 250,000 = 998 people.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.