A 5.00-wt% aqueous sulfuric acid solution (density=1.03 g/mL)flows through a 45-

Question

A 5.00-wt% aqueous sulfuric acid solution (density=1.03 g/mL)flows through a 45-m long pipe with a 6.0 cm diamete at a rate of87 L/min. (a) What is the molarity of the sulfuric acid in thesolution? (b) How long (in seconds) would it take to fill a 55-gallondrum and how much sulfuric acid (lbm) would the drum contain? (c) The mean velocity of a fluid in a pipe equals thevolumetris flow rate divided by the cross-sectional area normal tothe direction of flow. Use this information to estimate how long(in seconds) it takes the solution to flow from the pipe inlet tothe outlet. A 5.00-wt% aqueous sulfuric acid solution (density=1.03 g/mL)flows through a 45-m long pipe with a 6.0 cm diamete at a rate of87 L/min. (a) What is the molarity of the sulfuric acid in thesolution? (b) How long (in seconds) would it take to fill a 55-gallondrum and how much sulfuric acid (lbm) would the drum contain? (c) The mean velocity of a fluid in a pipe equals thevolumetris flow rate divided by the cross-sectional area normal tothe direction of flow. Use this information to estimate how long(in seconds) it takes the solution to flow from the pipe inlet tothe outlet.

Explanation / Answer

a)..................................

Sulfuric acid has a molecular mass of 98.08 g/mol

1.03 g/mL = 1030 g/L

( 5 g H2SO4 / 100g solution )( 1030 g/L ) / 98.08 g/mol = 0.5250 moles/L

b)..................................

1 liter = 0.264 gallon

(87 L/min)(0.264 gallon/L)( 1 min/60 sec ) = 0.3828 gal/sec

( 55 gal ) / ( 0.3828 gal/sec ) = 144 seconds

? = ( 1030 g/L )( 1 L/0.264 gallon )( 1 lbm/453.6 g ) = 8.601 lbm/gal

( 55 gal )( 8.601 lbm/gal ) = 473 lbm

c)..................................

A = ?D

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