What is the value of G when [Ag] = [Cu] = 1.0 M? I found the values for Ecell al

Question

What is the value of G when [Ag] = [Cu] = 1.0 M?

I found the values for Ecell already:

Ag+/Ag = 0.799
Cu2+/Cu = 0.340

(Can you do a step-by-step solution, and also explain what you used to determine the answer and why you used it to determine the answer? I am unsure about this topic and I need a little more clarity on how to do these problems.)

25,what is the value for 4G" when [Ag+]-[Cu2+]-1.0 M? Eo for Ag /Ag and CuCu are given in questions 19 & 24. (A) -44.4 kJ (B) -88.8 kJ (C) -243 kJ (D) 374 k

Explanation / Answer

Eo cell = Eo ( Ag+/Ag) - Eo ( Cu2+/Cu)

= 0.799-0.340 = 0.459

we have reaction 2Ag+ (aq) + Cu (s) ----> 2Ag (s) + Cu2+ (aq)

we use Nernest equation to calculate Ecell

E cell = Eo cell - ( 0.059/ n) log Q

where n = number of electrons involved per reaction = 2

Q cell ( reaction coefficient) = [Cu2+] / [Ag+]^2 = 1M / 1M^2 = 1 ,  

Ecell = 0.459 - ( 0.059/2) log (1)

= 0.459

now we have relation dG = - nFEcell where F = faraday constant = 96485 C

= - 2 x 96485 x 0.459 = -88570 J = -88.6 KJ

Hence answer is option B

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.