What is the total spin in the ground state configuration of oxygen molecule, O_2

Question

What is the total spin in the ground state configuration of oxygen molecule, O_2? 3 1 0 1/2 none of the above What is the highest occupied molecular orbital in I_2 molecule? sigma* sigma pi pi* none of the above Doppler broadening is caused by: the distribution of molecular sizes the distribution of translational velocities of atoms or molecules the uncertainty in the energy levels the uncertainty in the speed of molecular rotation the uncertainty in lifetimes Identify the nature of the electronic transitions associated with the peaks in the following UV/Vis spectrum: 1: pi Rightarrow pi*, 2: n Rightarrow sigma* 1: pi Rightarrow pi*, 2: n Rightarrow pi* 1: n Rightarrow pi*, 2: pi Rightarrow pi* 1: n Rightarrow sigma*, 2: pi Rightarrow pi* 1: n Rightarrow pi*, 2: n Rightarrow sigma*

Explanation / Answer

1) there are two unpaired electrons in the ground state of oxygen molecule

Hence the total spin = 1/2 + 1/2 = 1

2) The highest occupied molecular orbtial will be *

3) Doppler broadening is caused by distribution of translational velocities of atoms or molecules

4) we can identify the peaks based on max

The (2) peak is near 300 nm this must be due to extened conjugation of C=O , n __> *

The (1) peak is near 240 nm with high extinction coeffecient due to __> *

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.