Consider a cell based on the following line notation at 298 K: Consider a cell b

Question

Consider a cell based on the following line notation at 298 K:

Consider a cell based on the following line notation at 298 K: Cu | Cu2+ (O.261 M) 11 Pb2+ (1.23 M) I Pb Given: How many of the following responses are true? 1. Adding equal amounts of water to both half reactions will not change the potential of the cell 2. Decreasing the concentration of the Pb2+ will increase the potential of the cell 3. Increasing the concentration of the Cu2+ will increase the concentration of the reaction 4. Using a Pt electrode in place of the Cu electrode will not change the potential of the cell 5. Oxidation takes place at the anode 2 5 0 3 Submit Answer Tries 0/2

Explanation / Answer

COPPER WITH + VE POTENTIAL WORKS AS CATHODE AND LEAD AS ANODE WITH -VE POTENTIAL

Nernst equation, E = Eo - 0.059/2)log[Pb+2/Cu+2]

Q = [Pb+2/Cu+2]

1) TRUE -- SINCE DILUTION EFFECT IS SAME, NUMERATOR TO DENOMINATOR RATIO(Q VALUE) REMAINS CONSTANT.

2) TRUE -- IF CONCENTRATION OF Pb+2 DECRREASES , Q VALUE IN THE NERNST EQUATION DECREASES AND SO CELL POTENTIAL INCREASES.

3) TRUE --- THIS AGAIN DECREASES Q VALUE( QUIOTENT VALUE)

4) TRUE --- CELL POTENTIAL DOES NOT CHANGE , BUT PRODUCTS AT ELECTRODES CHANGES.

5) TRUE -- OXIDATION AT ANODE AND REDUCTION AT CATHODE.

ALL THE FIVE OPTIONS ARE TRUE.

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