1) 2Fe(s)+3Cl2(g)--> 2FeCl3(s) ?H= -687.6 kJ and ?S= -440.3 J/k at 253 K and 1 a

Question

1) 2Fe(s)+3Cl2(g)--> 2FeCl3(s)

?H= -687.6 kJ and ?S= -440.3 J/k at 253 K and 1 atm

The standard enthalpy change for the reaction of 1.55 moles of Fe (s) at this temperature would be___kJ. This reaction is a product or reactant favored under standard conditions at 253k

2) 2H2O2(l)-->2H2O(l) + O2(g)

?G= -237.9 kJ and ?H= -196.0 J/k at 333 K and 1 atm

The standard entropy change for the reaction of 1.82 moles of H2O2(l) at this temperature would be ____J/k. This reaction is a product or reactant favored under standard conditions at 333K.

3)Consider the reaction 2N2(g)+O2-->2N2O(g).

Use the standard thermodynamic data in the table linked above, calculate ?G for the reaction at 298.15K if the pressure of N2O(g) is reduced to 10.30 mm Hg, while the pressures of N2(g) and O2(g) remain at 1 atm ___kJ/mol

4)N2(g)+3H2(g)-->2NH3(g)

Using the standard thermodynamic data in the tables linked above, calculate ?Grxn for the reaction at 298.15K if the pressure of each gas is 11.13 mmHg ____kJ/ mol.

5) CO(g)+3H2(g)-->CH4(g)+H2O(g)

Using the standard thermodynamic data in the tables linked above, calculate ?G for this reaction at 298.15K if the pressure of each gas is 12.65mmHg___kJ/mol

6)2H2(g)+O2(g)-->2H2O(g)

?G=-461.2kJ and ?S=-88.9 J/K at 252K and 1 atm the maximum amount of work that could be done by this reaction when 2.21 moles of H2(g) react at standard conditions at this temperature is ___kJ.

7) CO(g)+H2O(l) --> CO2(g)+H2(g) ?H= -2.8 kJ and ?S=76.8 J/K

The maximum amount of work that could be don't when 1.56 moles if CO(g) react at 253K, 1atm is ____kJ. Assume that ?H and ?S are independent of temperature.

8) 2H2O(l)--> 2H2O(l)+O2(g)

The standard free energy change for this reaction is -233.4 kJ. The free energy change when 1.82 moles if H2O2(l) react at standard conditions is ____kJ. What is the maximum amount of useful work that the reaction of 1.82 moles of H2O2(l) is capable of producing in the surroundings under conditions? ____kJ

Explanation / Answer

1)

2Fe(s)+3Cl2(g)--> 2FeCl3(s)

dH = -687.6 kJ and dS = -440.3 J/K at 253K

for 2 moles of Fe dH = -687.6 kJ

then for 1.55 moles of Fe = -687.6*1.55/2 = -532.9 kJ

dH = -532.9 for 1.55 moles of Fe

the above reaction is products favoured reaction because the energy is released.

2)

2H2O2(l)-->2H2O(l) + O2(g)

dG = -237.9 kJ and dS = -196 J/K (based on units)

dS = -196 J/K for 2 moles of H2O then,

then for 1.82 moles H2O,

dS = -196*1.82/2

dS = -178.32 J/K at 333K

dS rxn = dS products - dS reactants

dS rxn = -ve means entropy of reaction is decreases so the products will be more stableo reaction is favoured to forward direction.

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