C3H6 + CO + H 2 C4H3O In an existing process, 180 kgmol/h of C,H, (P) is mixed w

Question

C3H6 + CO + H 2 C4H3O In an existing process, 180 kgmol/h of C,H, (P) is mixed with 420 kgmol/h of a mixture containing 50% CO (C) and 50% H, (H) and with a recycle stream containing propylene and then fed to a reactor. 30% of the propylene fed to the reactor is consumed. The reactor effluent is sent to a separator. The desired product butanal (B) s removed in one stream, unreacted CO and H, are removed in a second stream, and unreacted Pis recovered and recycled 6 P Mixer Reactor SeparatorC, H P, C, P, C,HH, B C,H 2 Suppose you have chosen the input-output diagram as your system. What are the material balance equations?

Explanation / Answer

Hydrogen In - consumed = Hydrogen out

hence option 3 is correct

since 30% reactor inlet Propylene is consumed, hence outlet will have 70% of initial amount

hence option 4 is correct

option 5 is correct because all the propylene that goes in has to be consumed since there is no outlet. This means all of it gets recycled till it is fully consumed.

Carbon mono oxide going out is equal to inlet - consumed, hence option 6 is correct

None of the B is getting recycled in separater hence B4 = B7. (B is not going out in stream 6)

B(gen) = B7 because all the B going out is generated inside the process. There is no input of B through feed.

P1 cannot be zero as it is a feed.

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