C3H6 + CO + H2 ? C4H80 In an existing process, 180 kgmol/h of C,H, (P) is mixed

Question

C3H6 + CO + H2 ? C4H80 In an existing process, 180 kgmol/h of C,H, (P) is mixed with 420 kgmol/h of a mixture containing 50% CO (C) and 50% H, (H) and with a recycle stream containing propylene and then fed to a reactor, 30% of the propylene fed to the reactor is consumed. The reactor effluent is sent to a separator. The desired product butanal (B) is removed in one stream, unreacted CO and H, are removed in a second stream, and unreacted P is recovered and recycled. 5 3 6 Mixer Reactor Separator P, C, H, B P, C, H C, H2 7 The process is correctly specified True False

Explanation / Answer

Specification is checked by degree of freedome analysis

Degree of freedom = number of unknown - number of equation

number of unknown = 03 ( 1 molar flow rate of B, 1 molar flow rate of C,1 molar flow rate of H)

Numer of equation = 03 ( 1 component balance for C,1 component balance for H, 1 reaction for B)

Degree of freedom = number of unknown - number of equation = 3-3 =0

so system correctly specified

True

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