If 480 g of a calcium iodide is dissolved in 933 g of watersolvent, calculate th

Question

If 480 g of a calcium iodide is dissolved in 933 g of watersolvent, calculate the magnitude (not the sign) of the boilingpoint elevation of the solution. Consider if the solute is anelectrolyte.


Molar Mass (g/mol) CaI2 293.89 H2O 18.015 Solvent Melting Point (oC) 0.00 Boiling Point (oC) 100.00 Kf (oC/m) 1.858 Kb (oC/m) 0.512 If 480 g of a calcium iodide is dissolved in 933 g of watersolvent, calculate the magnitude (not the sign) of the boilingpoint elevation of the solution. Consider if the solute is anelectrolyte.


Molar Mass (g/mol) CaI2 293.89 H2O 18.015 Solvent Melting Point (oC) 0.00 Boiling Point (oC) 100.00 Kf (oC/m) 1.858 Kb (oC/m) 0.512

Explanation / Answer

No. of moles of solute = 480/293.89 moles = 1.63 moles                       Mass of solvent = 933 gms = 0.933 kgs                  Molaltiy of solution = 1.63/0.933 m = 1.75 m                     Vant-hoff factor = no. of ions formed = 3                      Therefore, elevation in boiling point = vant-hoff factor xmolality x Kb = 2.69oC                     Thus, final boiling point = 102.69oC

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