If .934 grams of AgNO 3 (formula weight 169.91 g/mol)were reacted with 100mL of

Question

If .934 grams of AgNO3 (formula weight 169.91 g/mol)were reacted with 100mL of 0.100 M HCL to make AgCl(formula weight 143.35 g/mol) which reactant would be the limitingreagent and the theoretical yield of AgCl in grams?

Explanation / Answer

The balanced equation for the reaction is: AgNO3 +HCl => AgCl + HNO3 First off, you always want to get to moles if you don't know whatto do. Convert the mass of AgNO3 (.934g) into moles by dividingit by the molar mass (169.91 g/mol). To find the moles of HCl, multiply the Molarity (mol/Litersolution) by the amount of solution. This would be 0.100M x.100L   because 100mL is 1/10 of 1L. Whichever one has the lower number of moles is the limitingreagent. To find the theoretical yield, take the moles oflimiting reagent and convert to moles of AgCl using the molar ratio(1 to 1 in this case).

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