At 700 K, the reaction 2SO 2 (g) + O 2 (g) 2SO 3 (g) has the equilibrium constan

Question

At 700 K, the reaction 2SO2(g) + O2(g) 2SO3(g) has the equilibrium constant

Kc = 4.3 ´ 106, and thefollowing concentrations are present: [SO2] = 0.010 M;[SO3] = 10.0M;   [O2] = 0.010M.

Is the mixture at equilibrium? If not at equilibrium, inwhich direction (as the equation is written), left toright or right to left, will the reaction proceed toreach equilibrium?

A.     Yes, the mixture is atequilibrium.

B.     No, left to right

C.     No, right to left

D.     There is not enough information to beable to predict the direction.

Explanation / Answer

To check if the mixture is at equilibrium, we need to solvefor Qc and if it's bigger than Kc the mixturewill move to the left, if it's smaller, the mixture will move theright. Qc= (products)/( reactants)     = (10.0)2/(0.010)2(0.010)     = 1.0*108, which is bigger thanKc, that means the reaction is mostly reactants and it willmove to the right to
       proceed.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.