2SO 2 + 0 2 2SO 3 K eq = 2.8 x 10 2 Initially some SO 3 is placed in a container

Question

2SO2 + 02 2SO3       Keq= 2.8 x 102 Initially some SO3 is placed in a container andallowed to decompose. [SO3] at equilibrium is 4.5x 10-2 Find [O2] and [SO2] Please explain how to do this. Any help would beappriciated! 2SO2 + 02 2SO3       Keq= 2.8 x 102 Initially some SO3 is placed in a container andallowed to decompose. [SO3] at equilibrium is 4.5x 10-2 Find [O2] and [SO2] Please explain how to do this. Any help would beappriciated! Find [O2] and [SO2] Please explain how to do this. Any help would beappriciated!

Explanation / Answer

                         2SO2 + O2 2SO3       0 0          Y       +2x     +x       -2x Equilibrium:       2x       x         4.5e-2 K = [SO3]2 / ((SO2)2 (O2)) K = 2.8e2 = (4.5e-2)2 / (2x)2 (x) x = .012 [O2] = x = .012 [SO2] = 2x = 2(.012) = .024

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