A voltaic cell is created using a zinc electrode immersed in a1.0 M solution of

Question

A voltaic cell is created using a zinc electrode immersed in a1.0 M solution of Zn+2 ions and a silver electrodeimmersed in a solution of 1.0 M Ag+ ions. The twoelectrodes are connected with a wire, and a salt bridge is palcedbetweenthe two half-cells. The temperature of the cells is25oC. 1: What is the balanced half-reactions that are occurring atthe cathode and the anode. 2: Calculate the standard cell voltage for the cell. 3: Calculate G0 for the cell. 4: How will the voltage be affected if 2.5 g of KCl is addedto each half cell? Please justify your response. Thanks for the help, I really needed it! A voltaic cell is created using a zinc electrode immersed in a1.0 M solution of Zn+2 ions and a silver electrodeimmersed in a solution of 1.0 M Ag+ ions. The twoelectrodes are connected with a wire, and a salt bridge is palcedbetweenthe two half-cells. The temperature of the cells is25oC. 1: What is the balanced half-reactions that are occurring atthe cathode and the anode. 2: Calculate the standard cell voltage for the cell. 3: Calculate G0 for the cell. 4: How will the voltage be affected if 2.5 g of KCl is addedto each half cell? Please justify your response. Thanks for the help, I really needed it!

Explanation / Answer

Ag+ + e- =>Ag            E = 0.7996V Zn2+ + 2e- =>Zn          E =-0.7628V To make process spontaneous, we want a positive EMF, thus it isidentified that Zn is oxidized 2Ag+ + 2e- =>2Ag                 E =0.7996V                 cathode (reduction)            Zn=> Zn2+ +2e-          E =0.7628V                 anode    (oxidation) 2Ag+ + Zn => 2Ag + Zn2+       E =1.5624V                 standard cell voltage 3. delG0 = -n*F*E, where n is number of electrons and F = 96485C/mol delG0 = -2*96485C/mol *1.5624V = -123508.705 J/mol = -124kJ/mol 4. Ag+ precipitates with Cl- as AgCl. So the Ag+ concentration inthe cathode decreases. Thus, the potential in the cathodedecreases. Ideally nothing occurs in the anode because ZnCl2 issoluble and does not precipitate.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.