Calculate the concentration of borax solution (mol/L) if ittakes 0.76mL of 3M H

Question

Calculate the concentration of borax solution (mol/L) if ittakes 0.76mL of 3M H2SO4 to neutralize a 10mLsample of Borax. 2Na++ 2B(OH)4-+H2SO4--->2B(OH)3+2Na++SO42-+2H2O I'm having trouble with where to start and what the molecularformula is for borax? Calculate the concentration of borax solution (mol/L) if ittakes 0.76mL of 3M H2SO4 to neutralize a 10mLsample of Borax. 2Na++ 2B(OH)4-+H2SO4--->2B(OH)3+2Na++SO42-+2H2O I'm having trouble with where to start and what the molecularformula is for borax?

Explanation / Answer

No. of moles of H2SO4 is = Molarity *Volume in L                                        = 3M * ( 0.76 mL/ 1000 )                                        =0.00228 moles So, the no . of moles of Borax in the sample = No. of moles ofH2SO4 required to neutralize                                                                    =0.00228 moles Therefore concentration of Borax is ,M = No. of moles / Volumein L                                                             = 0.00228 / ( 10 /1000 )                                                             = 0.228 moles / L Molecular formula of Borax is Na2B4O7·10H2O

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