At 35 degrees Celsius, K=1.6 x 10 -5 for the reaction: 2NOCl (g) <===> 2NO (g) +

Question

At 35 degrees Celsius, K=1.6 x 10-5 for the reaction: 2NOCl(g) <===> 2NO(g) +Cl2(g)
Calculate the concentrations of all species atequilibrium for each of the following originalmixtures:
a) 2.0 mol pure NOCl in a 2.0 Lflask b) 1.0 mol NOCl and 1.0 mol NO in a 1.0 Lflask c) 2.0 mol NOCl and 1.0 molCl2 in a 1.0 L flask
The answers are : a) [NO]=0.032M, [Cl2]=0.016M, [NOCl]=1.0M b) [NO]=[NOCl]=1.0M,[Cl2]=1.6x10-5M c) [NO]=8.0x10-3M, [Cl2]=1.0M,[NOCl]=2.0M
BUT...how do you arrive at the answers? I need to know whatthe solution process is. K=1.6 x 10-5 for the reaction: 2NOCl(g) <===> 2NO(g) +Cl2(g)
Calculate the concentrations of all species atequilibrium for each of the following originalmixtures:
a) 2.0 mol pure NOCl in a 2.0 Lflask b) 1.0 mol NOCl and 1.0 mol NO in a 1.0 Lflask c) 2.0 mol NOCl and 1.0 molCl2 in a 1.0 L flask
The answers are : a) [NO]=0.032M, [Cl2]=0.016M, [NOCl]=1.0M b) [NO]=[NOCl]=1.0M,[Cl2]=1.6x10-5M c) [NO]=8.0x10-3M, [Cl2]=1.0M,[NOCl]=2.0M
BUT...how do you arrive at the answers? I need to know whatthe solution process is.

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