At 20 degrees C the vapor pressure of benzene(C 6 H 8 ) is 75 torr, and that of

Question

At 20 degrees C the vapor pressure of benzene(C6H8) is 75 torr, and that of toluene(C7H8) is 22 torr. assuming that benzene andtoluene from and Idea solution. A) what is the composition in mole fractions of a solutionthat has a vapor pressure of 33 torr at 20 degrees C C.) What is the mole fraction of benzene in thevapor above the solution describe in part A? At 20 degrees C the vapor pressure of benzene(C6H8) is 75 torr, and that of toluene(C7H8) is 22 torr. assuming that benzene andtoluene from and Idea solution. A) what is the composition in mole fractions of a solutionthat has a vapor pressure of 33 torr at 20 degrees C C.) What is the mole fraction of benzene in thevapor above the solution describe in part A?

Explanation / Answer

vapor pressure = x1*P1 + x2*P2 x1 = mol frac of component one P1 = vapor pressure of component one when pure x1 + x2 = 1 33 = x1*75 + (1-x1)*22 11 = (75 - 22)*x1 x1 = 0.20754717 ~ 0.21     x2 = 1 - x1 = 0.79 b) Raoult's law: x1*P1 = (P_vapor)*y1 y1 = composition in gas phase y1 = x1*P1/Pvap = (0.21*75)/33 = 0.471698114 ~ 0.47

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