Calculate the molality of an aqueous solutionthat contains 25.100 % (w/w) in KCN
ID: 691510 • Letter: C
Question
Calculate the molality of an aqueous solutionthat contains 25.100 % (w/w) in KCN.5.15 Calculate the mole fraction of KCN in thesolution described above (25.100 % (w/w) in KCN PLEASE I NEED THE SECOND PART ONLLY, BECAUSE 5.15 IS THEANSWER FOR THE FIRST PART Calculate the molality of an aqueous solutionthat contains 25.100 % (w/w) in KCN.
5.15 Calculate the mole fraction of KCN in thesolution described above (25.100 % (w/w) in KCN PLEASE I NEED THE SECOND PART ONLLY, BECAUSE 5.15 IS THEANSWER FOR THE FIRST PART
Explanation / Answer
We Know that : mole fraction of KCN = number of moles of KCN / Total number of molesof the solution numberof moles of KCN = 25.1 g / 65.1 g / mol = 0.385 moles number of moles of water = 74.9 g / 18 g /mol = 4.161 mol XKCN = nKCN / nKCN + nH2O = 0.385 moles / 0.385 moles + 4.161mol = 0.0846 = 0.385 moles / 0.385 moles + 4.161mol = 0.0846Related Questions
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