I approached this problem two ways. The first method Iused followed the format t

Question

I approached this problem two ways. The first method Iused followed the format the book laid out to a T but that left mewith molecules of water remaining after the reaction. So thenI tried a separate approach. The problem tells us that webegan with 15.01g of CuSO4*5H2O and thatafter the reaction there is only 9.60g of CuSO4remaining. I know that matter cannot be created or destroyedso the difference between the starting weight and the final weightwould be the water molecules that left. At least that is whatI am thinking. So I found the difference between the 15.01gand 9.60g which ended up as 5.41g of H2O. Then ifound the molar mass of H2O to be 18.016g/mol. Then i used the following conversion:

5.41g H2O X (1molH2O/ 18.016g H2O) X(6.022x1023 molecules of H2O/1mol H2O) =

1.81x1023 molecules H2O.

Did I do this correctly or have i gone astray? Please letme know thank you.

Explanation / Answer

"This water in the hydrate (referred to as "water ofhydration") can be removed by heating the hydrate. When allhydrating water is removed, the material is said to be anhydrousand is referred to as an anhydrate." "This water in the hydrate (referred to as "water ofhydration") can be removed by heating the hydrate. When allhydrating water is removed, the material is said to be anhydrousand is referred to as an anhydrate."

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