Item 36 Part A An open-end manometer containing mercury is connected to a contai
ID: 692106 • Letter: I
Question
Item 36 Part A An open-end manometer containing mercury is connected to a container of gas, as depicted in Sample Exercise 10.2 in the textbook. What is the pressure of the enclosed gas in torr in each of the following situations? The mercury in the arm attached to the gas is 14.5 cm higher than in the one open to the atmosphere atmospheric pressure is 0.965 atm Express your answer using three significant figures torr Submit My Answers Give Up Part B The mercury in the arm attached to the gas is 13 mm lower than in the one open to the atmosphere atmospheric pressure is 0.99 atm Express your answer using two significant figures torr Submit My Answers Give Up Provide Feedback ContinueExplanation / Answer
in the 1st case, the pressure of gas = atmospheric pressrue + difference in height* g* density of mercury
difference in height= 14.5 cm= 14.5/100 m = 0.145m, g= 9.8 m/sec2 and density= 13600 kg/m3
hence second term of equation = 0.145*9.8*13600 kg/m3=19326 N/m2
but 1 atm= 1.013*105 N/m2
19326 N/m2= 19326/1.013*105 atm =0.191 atm
pressure of gas= 0.965 +0.191 atm =1.156 atm=1.156*760 Torr =878.56 Torr
2. The pressrue is lower than the atmospheric pressure
hence pressrue of gas= atmospheric pressure- pressure due to level difference
pressure due to level difference = {(13/1000)m*9.8* 13600 N/m2/ 1.01*105 } atm =0.0171 atm
pressure of gas =0.99-0.0171 =0.9729 atm =0.9729*760 Torr =739.4 Torr
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