Most likely Lewis structure should be one in which; The total number of valence

Question

Most likely Lewis structure should be one in which;

The total number of valence electrons in C2H2 is 10 ( 4 from each C + 1 from each H).

Structure A:

In this structure, four bonds ( 8 electrons) and one lone pair ( 2 electrons) are present. So, the total number of valence electrons used are 10. Two carbon atoms complete their octets. The number of total bonds in this structure is 4.

Structure B:

In this structure, three bonds ( 6 electrons) and 4 lone pairs (8 electrons) are present. So, the total valence electrons used are 14. But the actual valence electrons in C2H2 is 10. So, this structure is not valid.

Structure C:

In this structure, three bonds (6 electrons) and 2 lone pairs (4 electrons) are present. So, the total valence electrons are 10. The two carbon atoms complete their octets. The number of total bonds is 3.

Structure D:

In this structure, five bonds (10 electrons) are present. So, the total valence electrons are 10. The two carbon atoms complete their octets. The number of total bonds 5.

Structure E:

In this structure, 4 bonds ( 8 electrons) and one lone pair (2 electrons). So, the total valence electrons are 10.

One carbon (positive charged carbon) does not complete its octet. So, this structure is not valid.

Structure A, C, and D are valid but structure D has more number of bonds.

Hence, the structure D is most likely Lewis structure.

Explanation / Answer

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