concentration = moles/Volume in L , concentrations (M) : NO2= 0.02/1=0.02, NO=0.

Question

concentration = moles/Volume in L , concentrations (M) : NO2= 0.02/1=0.02, NO=0.040/1=0.040, N2O= 0.015/1=0.015 and O2=0.0350, the reaction is NO2(g)+ NO(g)------->N2O(g)+ O2(g), deltaG1273=-9.67 Kj

Q= reaction coefficient =[N2O] [O2]/[NO2][NO] = 0.015*0.035/(0.02*0.040)=0.65

since deltaG=-RTlnK=-9.67KJ

since R= 8.314 J/mole.K, 9.67 Kj will have to be converted to Kj

hence 8.314*1273*lnK =9.67*1000, K=Equilibrium constant = 2.49

since Reaction coefficient <K, the reaction proceeds towards the products side. The reaction proceeds to reach equilibrium

Explanation / Answer

5. The reaction, NOd g ) + N0( g ) N20( g ) + Od g ) has @w,--9.67 kl. /G? G +Rtin reach equilibrium? G) 2-14013 KJ/mol the composition of the system if we begin the reaction with the pure products? Corwort malu to M 1273 A 1.00 L reaction vessel l at 1000.0 C contains 0.0200 mol NO,, 0.040 mol No, 0.015 mol N20, and O mol oz Is the reaction at equilibrium? If not, in which direction will the reaction proceed to 6. What is the value of the equilibrium constant for a reaction for which AG 07 What will happen to

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