Caleulation of pH from Hydrogen Ion Concentration pH a solution Ht concentration

Question

Caleulation of pH from Hydrogen Ion Concentration pH a solution Ht concentration of (a) 1.75 x 10-5 moVL; (b) 6.50 x 10-10 mo/L; (e) 1.0 x 10 molVL (d) 1.50 × 10-5 mol2 What is the of that has an Calculation of pH from Concentration of Strong Acid Calculate the pH of a solution prepared by diluting 3.0 mL of 2.5 M HCl to a final volume of 100 mL with H20. Calculation of the pH of a Mixture of a Weak Acid and Its Conjugate Base Calculate the pH of a dilute solution that contains a molar ratio of potassium acetate to acetic acid (pKa = 4.76) of : Using the Henderson-Hasselbalch equation, pH -pk, +los (A HA)

Explanation / Answer

Ans 1

Part a

[H+] = 1.75*10^-5 mol/L

pH = - log [H+]

= - log (1.75*10^-5)

= 4.76

Part b

[H+] = 6.50*10^-10 mol/L

pH = - log [H+]

= - log (6.50*10^-10)

= 9.19

Part c

[H+] = 1*10^-4 mol/L

pH = - log [H+]

= - log (1*10^-4)

= 4

Part d

[H+] = 1.5*10^-5 mol/L

pH = - log [H+]

= - log (1.5*10^-5)

= 4.82

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