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Chrome File Edit View History Bookmarks People Window Help 0 €, a Mon Jul 2 3:00:45 PM Charless ? 0 ? / O Recitation 7 (--> C fi e) https://learn.vccs.edu/bbcswebdav/pid-114991363-dt-content-rid-243578636-2/courses/GC297.CHM. 112.W01.SU18/GC297.CHM. 112.w. ::: Apps Online Banking-ur Credit Card Account LG HOME-myGCC LG HOME-myNVCC -Late Nite Labs Course selected. Pi vou VCU-Central Authc G FOREVER CHORDS b Recitation 7: » C: 8. Methanol can be made using the Fischer-Tropsch process according to the reaction CO (g) + 2 H2 (g) ? CH30H (9). The value of AH° for the reaction is -90.2 kJ/mol and the value of AG for the process is - 248 kJ/mol. a) Calculate the entropy change for the reaction at 25°C. b) Calculate the value of the equilibrium constant K at 25 C c) What is the equilibrium partial pressure of methanol (CHaOH (g)) in the above reaction, if the nitial partial pressures are Pco1 atm and PcH,OH 05 atm?

Explanation / Answer

a. DGo = DHo - TDSo

-24.8 kJ mol-1 = -90.2 kJ mol-1 - 298 K x DSo

Entropy change, DSo = -219.46 J K-1 mol-1

b. DGo = -RT ln K

ln K = 24.8 kJ mol-1 / (8.314 J K-1 mol-1 x 298 K) = 10.0

Equilibrium constant, K = 22026

c. K = PCH3OH / PCO x P2H2

CO + 2 H2 <-----------> CH3OH

I 1 0 0.5

C -x 2x -x

E 1-x 2x 0.5 - x

K = (0.5 + x) / (1-x)(2x)2 = 22026

88104 x2 - 88104 x3 = 0.5 - x

88104 x3 - 88104 x2 - x + 0.5 = 0

x = 0.0024, -0.0024, 1.000

x = -0.0024 is the only plausible solution.

equilibriu, pressure of CH3OH = 0.5 - (-0.0024) = 0.5024 atm

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