Chem In thermodynamics, we determine the spontaneity of a reaction by the sign o

Question

Chem

In thermodynamics, we determine the spontaneity of a reaction by the sign of Delta G. In electrochemistry, spontaneity is determined by the sign of . The values of Delta G and are related by the following formula: Delta G = -nF where n is the number of moles of electrons and F = 96,500J/V middot mol e- is the Faraday constant. The standard reduction potentials of lithium metal and chlorine gas are as follows: In a galvanic cell, the two half-reactions combine to 2Li(s) + Cl2(g) rightarrow 2LiCl(aq) Calculate the cell potential of this reaction under standard reaction conditions. Express your answer with the appropriate units. Calculate the free energy Delta G degree of the reaction. Express your answer with the appropriate units. In thermodynamics, we determine the spontaneity of a reaction by the sign of Delta G. In electrochemistry, spontaneity is determined by the sign of The values of Delta G and are related by the following formula: Delta G degree = -nF where n is the number of moles of electrons and F = 96,500J/V middot mol e- is the Faraday constant. What can be said about the spontaneity of this reaction?

Explanation / Answer

cell potential(E) = 4.4 V

free energy (G)= -nFE = -2*96500*4.4 = 849200 J/mol = 849.2 kJ/mol

free enegry is negative so, reaction is spontaneous as written

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