I already did it I just want to know if I did it right please help its detrement

Question

I already did it I just want to know if I did it right please help its detremental I do well on this

1. (20 points) If 675 mL of a 0.25 M lithium sulfide solution is reacted with an excess of copper (II) nitrate: a. What two products form, assuming it is a metathesis reaction, one in which the cations and anions switch in forming products? b. Write the whole, balanced reaction. c. What mass of each product forms? (30 points) If 830 mL of 0.18 M gold (III) acetate reacts with 595 mL of 0.26 2. M potassium chloride: a. What two products form, again assuming it is a metathesis reaction? b. Write the whole, balanced equation. c. Which is the limiting reactant? d. If0.87 g of gold (III) chloride forms, what is the percent yield?

Explanation / Answer

Ans 1

Part a

2 Li+(aq) + S2-(aq) + Cu2+(aq) + 2 NO3-(aq) CuS(s) + 2 Li+(aq) + 2 NO3-(aq)

Copper Sulfide in solid phase forms

Lithium nitrate in aqueous phase forms

Cation forms = 2 moles of Lithium ion (Li+)

Anion forms = 2 mole of Nitrate ion (NO3-)

Part b

Whole balanced reaction

Li2S(aq) + Cu(NO3)2 (aq) CuS(s) + 2 LiNO3 (aq)

Reaction type - double replacement

Part C

Moles of Lithium sulfide = molarity x volume

= 0.25 mol/L x 0.675 L

= 0.16875 mol

From the stoichiometry of the reaction

1 mol of Lithium sulfide produces = 2 mol of LiNO3

0.16875 mol Lithium sulfide produces = 2*0.16875 mol of LiNO3 = 0.3375 mol of LiNO3

Mass of LiNO3 formed = moles x molecular weight

= 0.3375 mol x 68.94 g/mol

= 23.267 g

From the stoichiometry of the reaction

1 mol of Lithium sulfide produces = 1 mol of CuS

0.16875 mol Lithium sulfide produces = 0.16875 mol  of CuS

Mass of CuS formed = moles x molecular weight

= 0.16875 mol x 95.611 g/mol

= 16.134 g

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