Chemistry help with pressure of mixture and mass of gas 6 Graded Edge session ma
ID: 711028 • Letter: C
Question
Chemistry help with pressure of mixture and mass of gas 6 Graded Edge session masteringchemistry.com/myct/itemView?offset-nextaassignmentProblemiD-98914648 Assignment 6-Graded Exercise 5.61 Part A Constants Pexiodic Table What is the total pressure of the mture? A gas moture contains each of the followng gases at the indicated partial pressures N 239 torr, Oz. 113 torr and He, 101 torr torr Submit Request Answer Part B What mass of each gas is present in a 135-sample of ts motre at 25 0° Enter your answers numerically separated by commas Nge Submit Incorrect; Try Again; 5 attempts remaining Provide Feedback O Type here to search
Explanation / Answer
part-A
partial pressur of N2= 239 torr
Partial pressure of O2= 113 torr
partial pressure of He=101 torr
Total pressure of gaseous mixture = 239 + 113 + 101 =453 torr
Total pressure of gaseous mixture = 453 torr
Part-B
partial pressure of N2 = 239 torr =0.314 atm
V= 1.35L
T=25.0C= 25.0+273= 298.0 K
R= 0.0821 L-atm/mole-k
PV= nRT
n= PV/RT
n= 0.314 x 1.35/0.0821x298 =0.017 moles
number of moles of N2= 0.017 moles
molar mass of N2= 28 grams
mass of 0.017 moles of N2= 0.017x28=0.476 grams
mass of N2= 0.476 grams
for O2
P= 113 torr=0.149 atm
n= 0.149 x1.35/0.0821x298=0.008 moles
molar mass of O2= 32 grams
mass of 0.008 moles of O2= 0.008x32 =0.256 grams
mass of O2= 0.256 grams
for He
P=101 torr=0.133 atm
n= 0.133x1.35/0.0821x298= 0.0073 moles
molar mass of He = 4 gram/mole
mass of 0.0073 moles of He= 0.0073 x4 = 0.0292 grams
mass of He= 0.029 grams.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.