What are the net ionic equations for the reactions (if any): 1- sodium sulfate +

Question

What are the net ionic equations for the reactions (if any):
1- sodium sulfate + lead(II) nitrate —>
2- NH3 (aq) + HClO4 (aq) —>
3- iron(II) bromide + lead —>
4- tin(IV) carbonate + perchloric acid
Thank you, What are the net ionic equations for the reactions (if any):
1- sodium sulfate + lead(II) nitrate —>
2- NH3 (aq) + HClO4 (aq) —>
3- iron(II) bromide + lead —>
4- tin(IV) carbonate + perchloric acid
Thank you,
1- sodium sulfate + lead(II) nitrate —>
2- NH3 (aq) + HClO4 (aq) —>
3- iron(II) bromide + lead —>
4- tin(IV) carbonate + perchloric acid 1- sodium sulfate + lead(II) nitrate —>
2- NH3 (aq) + HClO4 (aq) —>
3- iron(II) bromide + lead —>
4- tin(IV) carbonate + perchloric acid
Thank you,

Explanation / Answer

Ans-- For writing net ionic equation , firstly we have to write balence molecular equation and total net ionic equation as follows:

1 .The balence molecular equation between  sodium sulfate and lead(II) nitrate is

  Pb(NO3)2(aq)+ Na2SO4(aq) <====> PbSO4(solid) + 2NaNO3(aq)

For writing total ionic equation , the component in aqueous solution will split its constituents ion.

so, total net ionic equation is

2 Na+(aq) + SO42-(aq) + Pb2+(aq) + 2 NO3-(aq) PbSO4 (s) + 2 Na+(aq) + 2 NO3- (aq)

now , same ions in both side i,e spector ion will cancel to each other

therefore , net ionic equation is

Pb+2 (aq) + SO42-(aq) -----> PbSO4(s)

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