WINGRAVE Chem104 EXAM1Av mperature alloon is filled with He gas at sea level whe

Question

WINGRAVE Chem104 EXAM1Av mperature alloon is filled with He gas at sea level where the eaches 1.8e balloon expands to 61.2 L and the pressure 24. W temperature is 18°C, the reaches 1.85 atm. exp density of the He gas in the balloon at sea level? b) (2 pts) When the balloon reaches 30.000. feet, the temperature drops to -25.5°C and the volume of the balloon increases to 174. L. What is the balloon? c) (3 pts) If a mole of He leaked out of the balloon by the time it reached 30,0 ft, re-calculate the pressure in the balloon after the leaked He?

Explanation / Answer

24

a) first calculate mole of gas in baloon by using ideal gas equation

PV = nRT             where, P = atm pressure = 1.85 atm,

V = volume in Liter = 61.2 L

n = number of mole = ?

R = 0.08205L atm mol-1 K-1 =Proportionality constant = gas constant,

T = Temperature in K = 180C = 273.15+ 18 = 291.15 K

We can write ideal gas equation

n = PV/RT

Substitute the value

n = (1.85 X 61.2)/(0.08205 X 291.15) = 4.74 mole

baloon contain 4.74 mole He

molar mass of He = 4.0026 g/mol then 4.74 mole He = 4.74 X 4.0026 = 18.97 gm

Ballon contain 18.97 gm He gas

density = mass/volume

density of He in baloon = 18.97 / 61.2 = 0.31 gm/L

density of He in baloon = 0.31 gm/L

b) use ideal gas equation to calculate pressure

PV = nRT             where, P = atm pressure= ?

V = volume in Liter = 174 L

n = number of mole = 4.74 mol

R = 0.08205L atm mol-1 K-1 =Proportionality constant = gas constant,

T = Temperature in K = -25.50C = 273.15+ (-25.5) = 247.65 K

We can write ideal gas equation

P = nRT/V

Substitute value in above equation

P = (4.74 X 0.08205 X 247.65) / 174 = 0.5535 atm

pressure of He gas = 0.5535 atm

c) use ideal gas equation to calculate pressure

PV = nRT             where, P = atm pressure= ?

V = volume in Liter = 174 L

n = number of mole = 4.74 mol - 1 mole = 3.74

R = 0.08205L atm mol-1 K-1 =Proportionality constant = gas constant,

T = Temperature in K = -25.50C = 273.15+ (-25.5) = 247.65 K

We can write ideal gas equation

P = nRT/V

Substitute value in above equation

P = (3.74 X 0.08205 X 247.65) / 174 = 0.5535 atm

pressure of He gas = 0.4368 atm

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.