Hydrogen iodide can decompose into hydrogen and iodine gases. 2HI(g) H2(g) + I2(

Question

Hydrogen iodide can decompose into hydrogen and iodine gases.
2HI(g) H2(g) + I2(g)
Kp for the reaction is 0.016. If 0.200 atm of HI(g) is sealed in a flask, what is the pressure of each gas when equilibrium is established?

Explanation / Answer

2HI(g) =================> H2(g) + I2(g) I 0.200 x x C x x/2 x/2 E 0.200-x x/2 x/2 Let x be the partial pressure of H2 and I2 in equilibrium Equilibrium constant (Kp) = P(H2)P(I2)/P(HI)^2 0.016 = (x/2)*(x/2)/(0.200-x) = 0.016= (x^2/4)/(0.200-x) This is a quadratic equation. It will have two roots of x. they are -0.149 and 0.0855 So the pressure of H2 and I2 is (0.855/2)=0.425 atm

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