Apply what you know about the fundamental elements of a Grignard synthesis react

Question

Apply what you know about the fundamental elements of a Grignard synthesis reaction to answer the questions below about a reaction using the following data: 0.2601 g Mg reacted with 1.4907 g isopentyl bromide and 0.5430 g 1,4-cyclohexanedione 0.8787 g of the desired product were obtained Write a balanced equation for the reaction. Show calculations of numbers of moles and equivalences of each reagent used. Use that information to calculate the percent yield in this synthesis. Report all results to the maximum number of significant figures allowed.

Explanation / Answer

0.2601 g Mg = 0.0107 mol of Mg
1.4907 g isopentyl bromide(C5H11Br) = 9.8722*10-3 mol = 0.00987 mol

0.543 g 1,4-cyclohexanedione(C6H8O2) = 4.848*10-3 mol =0.004848 mol

Mg(0.0107 mol) + C5H11Br(0.00987 mol) = C5H11MgBr(0.00987 mol) + Mg(0.00083 mol)

thus there are more than 2 atoms of C5H11MgBr for each atom of C6H8O2

reaction

C6H8O2(0.004848 mol) + C5H11MgBr(0.00987 mol) ----(H+)----> C6H8O2H2(C5H11)2(0.004848 mol) +C5H11MgBr(0.000174 mol)

since all 1,4-cyclohexanedione(C6H8O2) gets converted to product

yield = 100%

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