Calculate the effective radiation dosage (in Sieverts) for a 71-kg person who is

Question

Calculate the effective radiation dosage (in Sieverts) for a 71-kg person who is exposed to 7.2 × 109 particles of alpha radiation. Assume that 91% of the radiation is absorbed, each alpha particle has an energy of 6.4× 10–13 J, and that the RBE of the alpha particles is 15. Note that RBE is sometimes called the quality factor, abbreviated as Q.

This has been answered wrong 3 times by Chegg. Remember that is 91% radiation absorbed, not 100%, as well as the answer being in Sv (Seiverts)

answer was 0.00088543, i answered it. don't need help anymore :)

Explanation / Answer

weight of person = 71kg

no. of alpha particles to which body is exposed = 7.2 X 109.

energy for one alpha particle = 6.4 X 10-13 J

Total energy absorbed = 7.2 X 109 X 6.4 X 10-13

= 46.08 X10-4 j

91% of the energy is absorbed therefore total energy absorbed by body = 91% of 46.08 X10-4 j

=0.004193 J

As, it is given that RBE = 15

therefore effective radiation dosage = 0.004193 X 15= 0.062899 J

in siverts effective radiation dosage =   effective radiation dosage/weight of body in Kg

= 0.062899 J/71 Kg

= 0.0008859042 Siverts

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