An electron found in the n = orbit has effectivelybeen removed from a hydrogen a

Question

An electron found in the n = orbit has effectivelybeen removed from a hydrogen atom . Use this information andcalculate the ionization energy in a) J per atom b) kJ/mol An electron found in the n = orbit has effectivelybeen removed from a hydrogen atom . Use this information andcalculate the ionization energy in a) J per atom b) kJ/mol

Explanation / Answer

E = 13.6 eV*(1/(n_initial)^2 - 1/(n_final)^2) n_initial = 1, the ground state E = 13.6 eV *(1/1^2 - 1/inf^2) => 13.6 eV *(1-0) = 13.6 eV Note 1/inf => 0 13.6 eV *(1.602 x 10^-19 J/1eV) = 2.18 e-18 J/atom b) 2.18 e-18 J/atom *(6.022e23 atom/1mol) *(1 kJ/1000 J ) = 1312kJ/mol

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