Calculate the standard entropy change for the reaction 2Na(s) + Cl2 (g) --> 2NaC

Question

Calculate the standard entropy change for the reaction 2Na(s) + Cl2 (g) --> 2NaCl (s) using the data from the following table: Substance Change in h Change in G S degrees 0.00 0.00 51.30 0.00 0.00 223.1 -411.0 -384.0 72.10

Explanation / Answer

Generally a compound will have a greater entropy when it is more dispersed, and therefore can exist in more microstates. In a reaction, if more molecules of product form, then entropy increases. Consider compound A: A(s) --> A(l) --> A(g) -------- entropy -------> Entropy increases as A goes from solid to liquid to gas. C6H12O6(s) -> 2C2H5OH(l) + 2CO2(g) Entropy increases. More molecules of products, and they are liquid and gas vs solid. P4(g) -> P4(s) Entropy decreases. Gas to solid. 2Na(s) + Cl2(g) -> 2NaCl(s) Entropy decreases. Number of particles decreases, and go from gas to solid.

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