Calculate the PH fat equivalence point in titrating 0.100 M solutions of each of

Question

Calculate the PH fat equivalence point in titrating 0.100 M solutions of each of the following with 0.080M NaOH;( a) chlorous acid (hclo2), (b)benzoic acid(c6h5cooh) will give more points for all the steps. please show all the steps

Explanation / Answer

part. NaClO is the salt. The ClO^- hydrolyzes in water as follows: .........ClO^- + HOH --> HClO + OH^- initial.0.0444.............0.....0 change...-x................x.....x equil..0.044-x..............x....x Kb for ClO^- = (Kw/Ka for HClO) = (HClO)(OH^-)/(ClO^-) Substitute from ICE chart above and solve for x = (OH^-) and convert to pH. The c part is just like the b part. For the a part, neither anion nor cation is hydrolyzed; therefore, the pH = 7. You do it this way. Take ANY volume acid, calculate the volume of the 0.08M base it will take to neutralize it, then moles salt (M x L) divided by TOTAL volume. It makes no difference what volume you take it will always end up 0.0444M for the 0.1M/0.08M case. HClO2 and NaOH gives you NaClO2

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