Calculate the cell potential of a cell operating with thefollowing reaction at 2

Question

Calculate the cell potential of a cell operating with thefollowing reaction at 25°C, in which[Cr2O72 ] = 0.030 M, [I ] = 0.019, M, [Cr3+ ] = 0.10 M, and [H+ ] = 0.60 M.

V

Explanation / Answer

Cr2O7 + 14H+ 6e-    -> 2Cr3+ + 7H2O       Ehalf =1.33                              6I- -> 3I2 +6e-                  Ehalf = -0.64 E0 = 0.69 V E = E0 - (RT/[nF]) *lnQ E = E0 - (RT/[nF]) *ln([Cr3+]2/{[H+]14[I-]6[Cr2O72-]} ) n = 6 mol e-; F = 96485 C/mol ; R = 8.314 J/mol/K; E = 0.69 - (8.314*298/[6*96485]) *ln([0.10]2/{[0.60]14[0.019]6 [0.03]}) E = 0.562 V

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.