https://ust35nc.theexpertta.com/Common/TakeTutorialAssignment.aspx Practice Assi

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https://ust35nc.theexpertta.com/Common/TakeTutorialAssignment.aspx Practice Assignment 5 (CH 5) Begin Date: 2/9/2018 6:00:00 AM-Due Date: 3/17/2018 11:59:00 PM End Date: 3/18/2018 2:00:00 AM (7%) Problem 13: A 60.0 kg skier with an initial speed of 13.5 m/s coasts up a 2.50 m high rise as shown in the figure. Randomized Variables v, 13.5 ms V-? KE, Vi 2.5 m 35° Ctheexpertta.com à Find her final speed right at the top, in meters per second, given that the coefficient of friction between her skis and the snow is 0.08. Grade Summary Deductions 9% Potential 100% leted leted pleted pleted pleted sin cos0) cotano asino acosO Submissien Attempts remaining (0% per attempt) detailed vien atan) acotan) sinh cos tanh) cotanho ·Degrees C) Radians ial Submit Hint I give up ial I linis:-% deduction per hint. Hints remaining: 2 Feedback: 0%ded action per feedback. mpleted search 0

Explanation / Answer

Here,

vi = 13.5 m/s

Now, let the final speed is vf

Using work energy theorum

0.50 *m * (vf^2 - vi^2) = - m * g * h - u * mg * cos(theta) * L/sin(theta)

0.50 * (vf^2 - 13.5^2) = -9.8 * 2.5 - 0.08 * 9.8 * cos(35 degree) * 2.5/sin(35 degree)

solving for vf

vf = 11.3 m/s

the final speed is 11.3 m/s

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